4x^2+12x+19=0

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Solution for 4x^2+12x+19=0 equation: 



4x^2+12x+19=0

a = 4; b = 12; c = +19;
Δ = b2-4ac
Δ = 122-4·4·19
Δ = -160
Delta is less than zero, so there is no solution for the equation

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